6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90..
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6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
Video solution 1: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2 cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2 cos150
Video solution 2: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2 cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2 cos150
Video solution 1: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2 cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2 cos150
Video solution 2: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2 cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2 cos150
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6 𝑐𝑜𝑠60−sin30+sin^2 45+𝑐𝑜𝑠^2 45#shorts #sslcexam2022
If sin 600° cos 30° + cos 120° sin 150° = k, then k = (a) 0 (b) 1 (c) −1 (d) None of these
If sin 600° cos 30° + cos 120° sin 150° = k, then k = (a) 0 (b) 1 (c) −1 (d) None of these
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If sin 600° cos 30° + cos 120° sin 150° = k, then k = (a) 0 (b) 1 (c) −1 (d) None of these
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